Base | Representation |
---|---|
bin | 110011010001001111… |
… | …000101011010110111 |
3 | 12021002112021202100221 |
4 | 303101033011122313 |
5 | 1400220300000210 |
6 | 41142320315211 |
7 | 3656122164661 |
oct | 632117053267 |
9 | 167075252327 |
10 | 55050000055 |
11 | 2138a320916 |
12 | a804172b07 |
13 | 5264086a3b |
14 | 29432c9531 |
15 | 1672dc61da |
hex | cd13c56b7 |
55050000055 has 8 divisors (see below), whose sum is σ = 66079757232. Its totient is φ = 44026828608.
The previous prime is 55050000041. The next prime is 55050000097. The reversal of 55050000055 is 55000005055.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55050000055 - 211 = 55049998007 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55049999984 and 55050000029.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1628022 + ... + 1661491.
It is an arithmetic number, because the mean of its divisors is an integer number (8259969654).
Almost surely, 255050000055 is an apocalyptic number.
55050000055 is a deficient number, since it is larger than the sum of its proper divisors (11029757177).
55050000055 is a wasteful number, since it uses less digits than its factorization.
55050000055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3292865.
The product of its (nonzero) digits is 3125, while the sum is 25.
Subtracting from 55050000055 its reverse (55000005055), we obtain a triangular number (49995000 = T9999).
The spelling of 55050000055 in words is "fifty-five billion, fifty million, fifty-five", and thus it is an aban number and an uban number.
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