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55050050005303 is a prime number
BaseRepresentation
bin11001000010001010101101…
…01011001110100100110111
321012220201210122012002120011
430201011112223032210313
524203420000300132203
6313025351023121051
714411143362255133
oct1441052653164467
9235821718162504
1055050050005303
11165a46600923a1
12621109a443187
132494274a148a2
14d846181ba3c3
15656ea130276d
hex321156ace937

55050050005303 has 2 divisors, whose sum is σ = 55050050005304. Its totient is φ = 55050050005302.

The previous prime is 55050050005277. The next prime is 55050050005369. The reversal of 55050050005303 is 30350005005055.

55050050005303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55050050005303 - 245 = 19865677916471 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55050050005903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27525025002651 + 27525025002652.

It is an arithmetic number, because the mean of its divisors is an integer number (27525025002652).

Almost surely, 255050050005303 is an apocalyptic number.

55050050005303 is a deficient number, since it is larger than the sum of its proper divisors (1).

55050050005303 is an equidigital number, since it uses as much as digits as its factorization.

55050050005303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28125, while the sum is 31.

The spelling of 55050050005303 in words is "fifty-five trillion, fifty billion, fifty million, five thousand, three hundred three".