Base | Representation |
---|---|
bin | 10000000001011111010… |
… | …00101001110100110101 |
3 | 1221122002010100210220021 |
4 | 20000233220221310311 |
5 | 33010014040000432 |
6 | 1100531012205141 |
7 | 54530160200263 |
oct | 10005750516465 |
9 | 1848063323807 |
10 | 550555000117 |
11 | 1a2541a43331 |
12 | 8a84b9097b1 |
13 | 3cbbcb8bb25 |
14 | 1c90b545433 |
15 | e4c40a7697 |
hex | 802fa29d35 |
550555000117 has 2 divisors, whose sum is σ = 550555000118. Its totient is φ = 550555000116.
The previous prime is 550555000087. The next prime is 550555000129. The reversal of 550555000117 is 711000555055.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 530739933361 + 19815066756 = 728519^2 + 140766^2 .
It is a cyclic number.
It is not a de Polignac number, because 550555000117 - 211 = 550554998069 is a prime.
It is a super-2 number, since 2×5505550001172 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550555000157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275277500058 + 275277500059.
It is an arithmetic number, because the mean of its divisors is an integer number (275277500059).
Almost surely, 2550555000117 is an apocalyptic number.
It is an amenable number.
550555000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
550555000117 is an equidigital number, since it uses as much as digits as its factorization.
550555000117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21875, while the sum is 34.
The spelling of 550555000117 in words is "five hundred fifty billion, five hundred fifty-five million, one hundred seventeen", and thus it is an aban number.
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