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550645314313 = 3934871399399
BaseRepresentation
bin10000000001101010000…
…01001011001100001001
31221122022102022020200111
420000311001023030021
533010210200024223
61100544000034321
754532334642053
oct10006501131411
91848272266614
10550645314313
111a2588a19766
128a8760029a1
133cc057c0a93
141c9195348d3
15e4cbe9730d
hex803504b309

550645314313 has 4 divisors (see below), whose sum is σ = 550647107200. Its totient is φ = 550643521428.

The previous prime is 550645314299. The next prime is 550645314367. The reversal of 550645314313 is 313413546055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313413546055 = 562682709211.

It is a cyclic number.

It is not a de Polignac number, because 550645314313 - 237 = 413206360841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (550645314113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306213 + ... + 1093186.

It is an arithmetic number, because the mean of its divisors is an integer number (137661776800).

Almost surely, 2550645314313 is an apocalyptic number.

It is an amenable number.

550645314313 is a deficient number, since it is larger than the sum of its proper divisors (1792887).

550645314313 is a wasteful number, since it uses less digits than its factorization.

550645314313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1792886.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 550645314313 in words is "five hundred fifty billion, six hundred forty-five million, three hundred fourteen thousand, three hundred thirteen".

Divisors: 1 393487 1399399 550645314313