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550714346754203 is a prime number
BaseRepresentation
bin111110100110111110010110…
…1000000101101000010011011
32200012220202222201011221020002
41331031330231000231002123
51034140400440232113303
65231134402301123215
7223666540620666212
oct17515745500550233
92605822881157202
10550714346754203
1114a524708716305
125192416855950b
131a83a1a8950468
1499dca06506079
1543a0525de0788
hex1f4df2d02d09b

550714346754203 has 2 divisors, whose sum is σ = 550714346754204. Its totient is φ = 550714346754202.

The previous prime is 550714346754199. The next prime is 550714346754259. The reversal of 550714346754203 is 302457643417055.

It is a happy number.

It is an a-pointer prime, because the next prime (550714346754259) can be obtained adding 550714346754203 to its sum of digits (56).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 550714346754203 - 22 = 550714346754199 is a prime.

It is a super-2 number, since 2×5507143467542032 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (550714346754703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275357173377101 + 275357173377102.

It is an arithmetic number, because the mean of its divisors is an integer number (275357173377102).

Almost surely, 2550714346754203 is an apocalyptic number.

550714346754203 is a deficient number, since it is larger than the sum of its proper divisors (1).

550714346754203 is an equidigital number, since it uses as much as digits as its factorization.

550714346754203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42336000, while the sum is 56.

The spelling of 550714346754203 in words is "five hundred fifty trillion, seven hundred fourteen billion, three hundred forty-six million, seven hundred fifty-four thousand, two hundred three".