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551000113 is a prime number
BaseRepresentation
bin100000110101111…
…001100000110001
31102101210201001121
4200311321200301
52112024000423
6130401502241
716440265216
oct4065714061
91371721047
10551000113
112630305a4
12134641981
138a200791
145326db0d
153358e45d
hex20d79831

551000113 has 2 divisors, whose sum is σ = 551000114. Its totient is φ = 551000112.

The previous prime is 551000111. The next prime is 551000117. The reversal of 551000113 is 311000155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 369100944 + 181899169 = 19212^2 + 13487^2 .

It is a cyclic number.

It is not a de Polignac number, because 551000113 - 21 = 551000111 is a prime.

It is a super-2 number, since 2×5510001132 = 607202249052025538, which contains 22 as substring.

Together with 551000111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (551000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275500056 + 275500057.

It is an arithmetic number, because the mean of its divisors is an integer number (275500057).

Almost surely, 2551000113 is an apocalyptic number.

It is an amenable number.

551000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

551000113 is an equidigital number, since it uses as much as digits as its factorization.

551000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 551000113 is about 23473.3915955918. The cubic root of 551000113 is about 819.8175843488.

Adding to 551000113 its reverse (311000155), we get a palindrome (862000268).

The spelling of 551000113 in words is "five hundred fifty-one million, one hundred thirteen", and thus it is an aban number.