Base | Representation |
---|---|
bin | 110011010100001111… |
… | …101111101111110001 |
3 | 12021020001022200020011 |
4 | 303110033233233301 |
5 | 1400321212130243 |
6 | 41151323014521 |
7 | 3660304364635 |
oct | 632417575761 |
9 | 167201280204 |
10 | 55100505073 |
11 | 21405886aa9 |
12 | a81906a441 |
13 | 527168ac73 |
14 | 2949cb4dc5 |
15 | 167755089d |
hex | cd43efbf1 |
55100505073 has 2 divisors, whose sum is σ = 55100505074. Its totient is φ = 55100505072.
The previous prime is 55100505071. The next prime is 55100505137. The reversal of 55100505073 is 37050500155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37689174769 + 17411330304 = 194137^2 + 131952^2 .
It is a cyclic number.
It is not a de Polignac number, because 55100505073 - 21 = 55100505071 is a prime.
Together with 55100505071, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55100505071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27550252536 + 27550252537.
It is an arithmetic number, because the mean of its divisors is an integer number (27550252537).
Almost surely, 255100505073 is an apocalyptic number.
It is an amenable number.
55100505073 is a deficient number, since it is larger than the sum of its proper divisors (1).
55100505073 is an equidigital number, since it uses as much as digits as its factorization.
55100505073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13125, while the sum is 31.
The spelling of 55100505073 in words is "fifty-five billion, one hundred million, five hundred five thousand, seventy-three".
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