Search a number
-
+
55102114981 is a prime number
BaseRepresentation
bin110011010100010101…
…111000110010100101
312021020011100110121101
4303110111320302211
51400322120134411
641151421320101
73660324151354
oct632425706245
9167204313541
1055102114981
1121406786601
12a819706031
135271b02984
14294a1b399b
15167776c8c1
hexcd4578ca5

55102114981 has 2 divisors, whose sum is σ = 55102114982. Its totient is φ = 55102114980.

The previous prime is 55102114973. The next prime is 55102115039. The reversal of 55102114981 is 18941120155.

It is a happy number.

55102114981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49753533025 + 5348581956 = 223055^2 + 73134^2 .

It is a cyclic number.

It is not a de Polignac number, because 55102114981 - 23 = 55102114973 is a prime.

It is a super-2 number, since 2×551021149812 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55102114981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55102114901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27551057490 + 27551057491.

It is an arithmetic number, because the mean of its divisors is an integer number (27551057491).

Almost surely, 255102114981 is an apocalyptic number.

It is an amenable number.

55102114981 is a deficient number, since it is larger than the sum of its proper divisors (1).

55102114981 is an equidigital number, since it uses as much as digits as its factorization.

55102114981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 37.

The spelling of 55102114981 in words is "fifty-five billion, one hundred two million, one hundred fourteen thousand, nine hundred eighty-one".