Base | Representation |
---|---|
bin | 10000000010011000010… |
… | …00011101011101010011 |
3 | 1221200022102222210210121 |
4 | 20001030020131131103 |
5 | 33012003433200430 |
6 | 1101050251411111 |
7 | 54545054032651 |
oct | 10011410353523 |
9 | 1850272883717 |
10 | 551033100115 |
11 | 1a27679019a3 |
12 | 8a963a53a97 |
13 | 3cc67c46a34 |
14 | 1c954c39dd1 |
15 | e501046a7a |
hex | 804c21d753 |
551033100115 has 4 divisors (see below), whose sum is σ = 661239720144. Its totient is φ = 440826480088.
The previous prime is 551033100089. The next prime is 551033100139. The reversal of 551033100115 is 511001330155.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 551033100115 - 237 = 413594146643 is a prime.
It is a super-2 number, since 2×5510331001152 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 551033100115.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55103310007 + ... + 55103310016.
It is an arithmetic number, because the mean of its divisors is an integer number (165309930036).
Almost surely, 2551033100115 is an apocalyptic number.
551033100115 is a deficient number, since it is larger than the sum of its proper divisors (110206620029).
551033100115 is a wasteful number, since it uses less digits than its factorization.
551033100115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110206620028.
The product of its (nonzero) digits is 1125, while the sum is 25.
The spelling of 551033100115 in words is "five hundred fifty-one billion, thirty-three million, one hundred thousand, one hundred fifteen".
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