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551211400253 is a prime number
BaseRepresentation
bin10000000010101101100…
…00100111110000111101
31221200202212111101121102
420001112300213300331
533012340104302003
61101120101142445
754552350411303
oct10012660476075
91850685441542
10551211400253
111a2849513488
128a9b36baa25
133cc95b73c87
141c9707b0273
15e511a16588
hex8056c27c3d

551211400253 has 2 divisors, whose sum is σ = 551211400254. Its totient is φ = 551211400252.

The previous prime is 551211400183. The next prime is 551211400261. The reversal of 551211400253 is 352004112155.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 340680007684 + 210531392569 = 583678^2 + 458837^2 .

It is a cyclic number.

It is not a de Polignac number, because 551211400253 - 28 = 551211399997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551211402253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275605700126 + 275605700127.

It is an arithmetic number, because the mean of its divisors is an integer number (275605700127).

Almost surely, 2551211400253 is an apocalyptic number.

It is an amenable number.

551211400253 is a deficient number, since it is larger than the sum of its proper divisors (1).

551211400253 is an equidigital number, since it uses as much as digits as its factorization.

551211400253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 29.

The spelling of 551211400253 in words is "five hundred fifty-one billion, two hundred eleven million, four hundred thousand, two hundred fifty-three".