Base | Representation |
---|---|
bin | 10000000010101101100… |
… | …00101000010000001101 |
3 | 1221200202212111111100111 |
4 | 20001112300220100031 |
5 | 33012340104333003 |
6 | 1101120101200021 |
7 | 54552350420161 |
oct | 10012660502015 |
9 | 1850685444314 |
10 | 551211402253 |
11 | 1a2849514a36 |
12 | 8a9b3700011 |
13 | 3cc95b74b65 |
14 | 1c9707b0ca1 |
15 | e511a16e6d |
hex | 8056c2840d |
551211402253 has 2 divisors, whose sum is σ = 551211402254. Its totient is φ = 551211402252.
The previous prime is 551211402241. The next prime is 551211402277. The reversal of 551211402253 is 352204112155.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 371128295209 + 180083107044 = 609203^2 + 424362^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-551211402253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (551211400253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275605701126 + 275605701127.
It is an arithmetic number, because the mean of its divisors is an integer number (275605701127).
Almost surely, 2551211402253 is an apocalyptic number.
It is an amenable number.
551211402253 is a deficient number, since it is larger than the sum of its proper divisors (1).
551211402253 is an equidigital number, since it uses as much as digits as its factorization.
551211402253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 551211402253 in words is "five hundred fifty-one billion, two hundred eleven million, four hundred two thousand, two hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •