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551211402253 is a prime number
BaseRepresentation
bin10000000010101101100…
…00101000010000001101
31221200202212111111100111
420001112300220100031
533012340104333003
61101120101200021
754552350420161
oct10012660502015
91850685444314
10551211402253
111a2849514a36
128a9b3700011
133cc95b74b65
141c9707b0ca1
15e511a16e6d
hex8056c2840d

551211402253 has 2 divisors, whose sum is σ = 551211402254. Its totient is φ = 551211402252.

The previous prime is 551211402241. The next prime is 551211402277. The reversal of 551211402253 is 352204112155.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 371128295209 + 180083107044 = 609203^2 + 424362^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551211402253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551211400253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275605701126 + 275605701127.

It is an arithmetic number, because the mean of its divisors is an integer number (275605701127).

Almost surely, 2551211402253 is an apocalyptic number.

It is an amenable number.

551211402253 is a deficient number, since it is larger than the sum of its proper divisors (1).

551211402253 is an equidigital number, since it uses as much as digits as its factorization.

551211402253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 551211402253 in words is "five hundred fifty-one billion, two hundred eleven million, four hundred two thousand, two hundred fifty-three".