Base | Representation |
---|---|
bin | 10000000010111011110… |
… | …10000010111001101111 |
3 | 1221201002020010111112011 |
4 | 20001131322002321233 |
5 | 33013111303424330 |
6 | 1101140023222051 |
7 | 54555334552036 |
oct | 10013572027157 |
9 | 1851066114464 |
10 | 551331311215 |
11 | 1a2900174353 |
12 | 8aa278a7927 |
13 | 3ccb49694c9 |
14 | 1c9826a571d |
15 | e51c30082a |
hex | 805de82e6f |
551331311215 has 4 divisors (see below), whose sum is σ = 661597573464. Its totient is φ = 441065048968.
The previous prime is 551331311197. The next prime is 551331311249. The reversal of 551331311215 is 512113133155.
551331311215 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 551331311215 - 231 = 549183827567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55133131117 + ... + 55133131126.
It is an arithmetic number, because the mean of its divisors is an integer number (165399393366).
Almost surely, 2551331311215 is an apocalyptic number.
551331311215 is a deficient number, since it is larger than the sum of its proper divisors (110266262249).
551331311215 is a wasteful number, since it uses less digits than its factorization.
551331311215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110266262248.
The product of its digits is 6750, while the sum is 31.
The spelling of 551331311215 in words is "five hundred fifty-one billion, three hundred thirty-one million, three hundred eleven thousand, two hundred fifteen".
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