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551343132463 is a prime number
BaseRepresentation
bin10000000010111101001…
…11001000111100101111
31221201010001101002020011
420001132213020330233
533013122320214323
61101141124434051
754555540205234
oct10013647107457
91851101332204
10551343132463
111a2906908882
128aa2b848927
133ccb7248026
141c9840a178b
15e51d38820d
hex805e9c8f2f

551343132463 has 2 divisors, whose sum is σ = 551343132464. Its totient is φ = 551343132462.

The previous prime is 551343132413. The next prime is 551343132503. The reversal of 551343132463 is 364231343155.

551343132463 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (551343132503) can be obtained adding 551343132463 to its sum of digits (40).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 551343132463 - 233 = 542753197871 is a prime.

It is a super-2 number, since 2×5513431324632 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (551343132413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275671566231 + 275671566232.

It is an arithmetic number, because the mean of its divisors is an integer number (275671566232).

Almost surely, 2551343132463 is an apocalyptic number.

551343132463 is a deficient number, since it is larger than the sum of its proper divisors (1).

551343132463 is an equidigital number, since it uses as much as digits as its factorization.

551343132463 is an evil number, because the sum of its binary digits is even.

The product of its digits is 388800, while the sum is 40.

The spelling of 551343132463 in words is "five hundred fifty-one billion, three hundred forty-three million, one hundred thirty-two thousand, four hundred sixty-three".