Base | Representation |
---|---|
bin | 10000000010111110100… |
… | …10001100101101000011 |
3 | 1221201010211121112212101 |
4 | 20001133102030231003 |
5 | 33013133212420120 |
6 | 1101142210411231 |
7 | 54556035146506 |
oct | 10013722145503 |
9 | 1851124545771 |
10 | 551354420035 |
11 | 1a2912218351 |
12 | 8aa33590b17 |
13 | 3ccb969a973 |
14 | 1c98579d13d |
15 | e51e36790a |
hex | 805f48cb43 |
551354420035 has 4 divisors (see below), whose sum is σ = 661625304048. Its totient is φ = 441083536024.
The previous prime is 551354420017. The next prime is 551354420117. The reversal of 551354420035 is 530024453155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 551354420035 - 27 = 551354419907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 551354419976 and 551354420003.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55135441999 + ... + 55135442008.
It is an arithmetic number, because the mean of its divisors is an integer number (165406326012).
Almost surely, 2551354420035 is an apocalyptic number.
551354420035 is a deficient number, since it is larger than the sum of its proper divisors (110270884013).
551354420035 is a wasteful number, since it uses less digits than its factorization.
551354420035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110270884012.
The product of its (nonzero) digits is 180000, while the sum is 37.
The spelling of 551354420035 in words is "five hundred fifty-one billion, three hundred fifty-four million, four hundred twenty thousand, thirty-five".
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