55140401311 has 4 divisors (see below), whose sum is σ = 55156810624. Its totient is φ = 55123992000.

The previous prime is 55140401293. The next prime is 55140401369. The reversal of 55140401311 is 11310404155.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11310404155 = 5 ⋅2262080831.

It is a cyclic number.

It is not a de Polignac number, because 55140401311 - 2¹⁷ = 55140270239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55140401711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8199615 + ... + 8206336.

It is an arithmetic number, because the mean of its divisors is an integer number (13789202656).

Almost surely, 2^55140401311 is an apocalyptic number.

55140401311 is a deficient number, since it is larger than the sum of its proper divisors (16409313).

55140401311 is a wasteful number, since it uses less digits than its factorization.

55140401311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16409312.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 55140401311 its reverse (11310404155), we get a palindrome (66450805466).

The spelling of 55140401311 in words is "fifty-five billion, one hundred forty million, four hundred one thousand, three hundred eleven".