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55214313474317 is a prime number
BaseRepresentation
bin11001000110111100101011…
…00010101000100100001101
321020111102210102212220112212
430203132111202220210031
524214112403222134232
6313233034435240205
714426050105565144
oct1443362542504415
9236442712786485
1055214313474317
1116658293581968
126238aa1a49065
1324a68c235012a
14d8c55c02875b
1565b3b7209eb2
hex3237958a890d

55214313474317 has 2 divisors, whose sum is σ = 55214313474318. Its totient is φ = 55214313474316.

The previous prime is 55214313474197. The next prime is 55214313474337. The reversal of 55214313474317 is 71347431341255.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48959282462281 + 6255031012036 = 6997091^2 + 2501006^2 .

It is a cyclic number.

It is not a de Polignac number, because 55214313474317 - 212 = 55214313470221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55214313474337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27607156737158 + 27607156737159.

It is an arithmetic number, because the mean of its divisors is an integer number (27607156737159).

Almost surely, 255214313474317 is an apocalyptic number.

It is an amenable number.

55214313474317 is a deficient number, since it is larger than the sum of its proper divisors (1).

55214313474317 is an equidigital number, since it uses as much as digits as its factorization.

55214313474317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4233600, while the sum is 50.

The spelling of 55214313474317 in words is "fifty-five trillion, two hundred fourteen billion, three hundred thirteen million, four hundred seventy-four thousand, three hundred seventeen".