Base | Representation |
---|---|
bin | 11001000111010001001101… |
… | …11101101111110111001000 |
3 | 21020112111021010021200120222 |
4 | 30203220212331233313020 |
5 | 24214303000330304000 |
6 | 313242101125005212 |
7 | 14426620326040532 |
oct | 1443504675576710 |
9 | 236474233250528 |
10 | 55225343213000 |
11 | 16661a33581884 |
12 | 623b05b853808 |
13 | 24a795c48a81c |
14 | d8ccc6c3a852 |
15 | 65b8106c0a85 |
hex | 323a26f6fdc8 |
55225343213000 has 32 divisors (see below), whose sum is σ = 129227303120760. Its totient is φ = 22090137284800.
The previous prime is 55225343212973. The next prime is 55225343213071. The reversal of 55225343213000 is 31234352255.
It can be written as a sum of positive squares in 4 ways, for example, as 7193263464676 + 48032079748324 = 2682026^2 + 6930518^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27612670607 + ... + 27612672606.
Almost surely, 255225343213000 is an apocalyptic number.
55225343213000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
55225343213000 is an abundant number, since it is smaller than the sum of its proper divisors (74001959907760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
55225343213000 is a wasteful number, since it uses less digits than its factorization.
55225343213000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55225343234 (or 55225343220 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 55225343213000 its reverse (31234352255), we get a palindrome (55256577565255).
The spelling of 55225343213000 in words is "fifty-five trillion, two hundred twenty-five billion, three hundred forty-three million, two hundred thirteen thousand".
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