Base | Representation |
---|---|
bin | 111110110010001011111100… |
… | …0000001111101100000111111 |
3 | 2200102101002120221211020100201 |
4 | 1331210113320001331200333 |
5 | 1034341122424343310110 |
6 | 5234314334513304331 |
7 | 224216063266150135 |
oct | 17544277001754077 |
9 | 2612332527736321 |
10 | 552255351150655 |
11 | 14aa691a7503649 |
12 | 51b329538650a7 |
13 | 1a91c5c1235639 |
14 | 9a534318b3755 |
15 | 43ca668020b3a |
hex | 1f645f807d83f |
552255351150655 has 32 divisors (see below), whose sum is σ = 707213012688000. Its totient is φ = 412554233659392.
The previous prime is 552255351150589. The next prime is 552255351150673. The reversal of 552255351150655 is 556051153552255.
It is a cyclic number.
It is not a de Polignac number, because 552255351150655 - 213 = 552255351142463 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 552255351150596 and 552255351150605.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40273840 + ... + 52215829.
It is an arithmetic number, because the mean of its divisors is an integer number (22100406646500).
Almost surely, 2552255351150655 is an apocalyptic number.
552255351150655 is a deficient number, since it is larger than the sum of its proper divisors (154957661537345).
552255351150655 is a wasteful number, since it uses less digits than its factorization.
552255351150655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92490243.
The product of its (nonzero) digits is 28125000, while the sum is 55.
The spelling of 552255351150655 in words is "five hundred fifty-two trillion, two hundred fifty-five billion, three hundred fifty-one million, one hundred fifty thousand, six hundred fifty-five".
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