Base | Representation |
---|---|
bin | 11001000111011101000101… |
… | …01000111100010101110011 |
3 | 21020120002201001100112110002 |
4 | 30203232202220330111303 |
5 | 24214404022023214141 |
6 | 313245033153500215 |
7 | 14430234224145215 |
oct | 1443564250742563 |
9 | 236502631315402 |
10 | 55231713101171 |
11 | 16664702181072 |
12 | 6240338b7166b |
13 | 24a8436084019 |
14 | d8d32cc125b5 |
15 | 65ba84a1ee9b |
hex | 323ba2a3c573 |
55231713101171 has 4 divisors (see below), whose sum is σ = 55520884374144. Its totient is φ = 54942541828200.
The previous prime is 55231713101083. The next prime is 55231713101183. The reversal of 55231713101171 is 17110131713255.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55231713101171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55231713100171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144585636200 + ... + 144585636581.
It is an arithmetic number, because the mean of its divisors is an integer number (13880221093536).
Almost surely, 255231713101171 is an apocalyptic number.
55231713101171 is a deficient number, since it is larger than the sum of its proper divisors (289171272973).
55231713101171 is a wasteful number, since it uses less digits than its factorization.
55231713101171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 289171272972.
The product of its (nonzero) digits is 22050, while the sum is 38.
The spelling of 55231713101171 in words is "fifty-five trillion, two hundred thirty-one billion, seven hundred thirteen million, one hundred one thousand, one hundred seventy-one".
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