Base | Representation |
---|---|
bin | 110011011100001101… |
… | …011101011010111111 |
3 | 12021120100202012012010 |
4 | 303130031131122333 |
5 | 1401104413422310 |
6 | 41212454542303 |
7 | 3663516205620 |
oct | 633415353277 |
9 | 167510665163 |
10 | 55234123455 |
11 | 2147424a515 |
12 | a855967993 |
13 | 52932726b4 |
14 | 295d937a47 |
15 | 1684146320 |
hex | cdc35d6bf |
55234123455 has 32 divisors (see below), whose sum is σ = 101103105024. Its totient is φ = 25223993856.
The previous prime is 55234123453. The next prime is 55234123493. The reversal of 55234123455 is 55432143255.
It is not a de Polignac number, because 55234123455 - 21 = 55234123453 is a prime.
It is a super-3 number, since 3×552341234553 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55234123453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 166627 + ... + 371796.
It is an arithmetic number, because the mean of its divisors is an integer number (3159472032).
Almost surely, 255234123455 is an apocalyptic number.
55234123455 is a deficient number, since it is larger than the sum of its proper divisors (45868981569).
55234123455 is a wasteful number, since it uses less digits than its factorization.
55234123455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 539415.
The product of its digits is 360000, while the sum is 39.
The spelling of 55234123455 in words is "fifty-five billion, two hundred thirty-four million, one hundred twenty-three thousand, four hundred fifty-five".
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