Search a number
-
+
5525544403 = 23240241061
BaseRepresentation
bin1010010010101100…
…10001110111010011
3112021002021201221201
411021112101313103
542304014410103
62312143332031
7253633231621
oct51126216723
915232251851
105525544403
112386031325
1210a25b1017
136a09b8902
143a5bc6511
1522516851d
hex149591dd3

5525544403 has 4 divisors (see below), whose sum is σ = 5765785488. Its totient is φ = 5285303320.

The previous prime is 5525544389. The next prime is 5525544407. The reversal of 5525544403 is 3044455255.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5525544403 - 217 = 5525413331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5525544407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120120508 + ... + 120120553.

It is an arithmetic number, because the mean of its divisors is an integer number (1441446372).

Almost surely, 25525544403 is an apocalyptic number.

5525544403 is a deficient number, since it is larger than the sum of its proper divisors (240241085).

5525544403 is a wasteful number, since it uses less digits than its factorization.

5525544403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 240241084.

The product of its (nonzero) digits is 240000, while the sum is 37.

The square root of 5525544403 is about 74334.0056972581. The cubic root of 5525544403 is about 1767.9026945408.

Adding to 5525544403 its reverse (3044455255), we get a palindrome (8569999658).

The spelling of 5525544403 in words is "five billion, five hundred twenty-five million, five hundred forty-four thousand, four hundred three".

Divisors: 1 23 240241061 5525544403