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55301312143 = 7211102599837
BaseRepresentation
bin110011100000001101…
…110000111010001111
312021202001011201202001
4303200031300322033
51401224113442033
641223255013131
73665263253200
oct634015607217
9167661151661
1055301312143
11214a9170360
12a87436a1a7
1352a416870c
1429688275a7
151689eb8e7d
hexce0370e8f

55301312143 has 12 divisors (see below), whose sum is σ = 70178289192. Its totient is φ = 43091931120.

The previous prime is 55301312141. The next prime is 55301312189. The reversal of 55301312143 is 34121310355.

It is a happy number.

55301312143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 55301312143 - 21 = 55301312141 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55301312141) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 51299380 + ... + 51300457.

It is an arithmetic number, because the mean of its divisors is an integer number (5848190766).

Almost surely, 255301312143 is an apocalyptic number.

55301312143 is a deficient number, since it is larger than the sum of its proper divisors (14876977049).

55301312143 is a wasteful number, since it uses less digits than its factorization.

55301312143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102599862 (or 102599855 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 55301312143 its reverse (34121310355), we get a palindrome (89422622498).

The spelling of 55301312143 in words is "fifty-five billion, three hundred one million, three hundred twelve thousand, one hundred forty-three".

Divisors: 1 7 11 49 77 539 102599837 718198859 1128598207 5027392013 7900187449 55301312143