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553045413553541 is a prime number
BaseRepresentation
bin111110110111111011110101…
…1011010110110010110000101
32200112011121212202121201212222
41331233313223122312112011
51034442044001332203131
65240121320000422125
7224330132623602626
oct17557675332662605
92615147782551788
10553045413553541
111502432740a5567
125203baa6017945
131a978c6040341c
149a7d7800bba4d
1543e0ea8b7e87b
hex1f6fdeb6b6585

553045413553541 has 2 divisors, whose sum is σ = 553045413553542. Its totient is φ = 553045413553540.

The previous prime is 553045413553379. The next prime is 553045413553543. The reversal of 553045413553541 is 145355314540355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 339202317162916 + 213843096390625 = 18417446^2 + 14623375^2 .

It is a cyclic number.

It is not a de Polignac number, because 553045413553541 - 210 = 553045413552517 is a prime.

Together with 553045413553543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (553045413553543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 276522706776770 + 276522706776771.

It is an arithmetic number, because the mean of its divisors is an integer number (276522706776771).

Almost surely, 2553045413553541 is an apocalyptic number.

It is an amenable number.

553045413553541 is a deficient number, since it is larger than the sum of its proper divisors (1).

553045413553541 is an equidigital number, since it uses as much as digits as its factorization.

553045413553541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000000, while the sum is 53.

The spelling of 553045413553541 in words is "five hundred fifty-three trillion, forty-five billion, four hundred thirteen million, five hundred fifty-three thousand, five hundred forty-one".