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553102001133 = 31116760666701
BaseRepresentation
bin10000000110001110111…
…00101100001111101101
31221212122121222212110020
420003013130230033231
533030223103014013
61102031435232353
754650245303233
oct10030734541755
91855577885406
10553102001133
111a3629729950
128b2408a86b9
1340207766616
141caad90c953
15e5c29b9623
hex80c772c3ed

553102001133 has 8 divisors (see below), whose sum is σ = 804512001696. Its totient is φ = 335213334000.

The previous prime is 553102001071. The next prime is 553102001149. The reversal of 553102001133 is 331100201355.

553102001133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 553102001133 - 29 = 553102000621 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (553102001533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8380333318 + ... + 8380333383.

It is an arithmetic number, because the mean of its divisors is an integer number (100564000212).

Almost surely, 2553102001133 is an apocalyptic number.

It is an amenable number.

553102001133 is a deficient number, since it is larger than the sum of its proper divisors (251410000563).

553102001133 is a wasteful number, since it uses less digits than its factorization.

553102001133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16760666715.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 553102001133 its reverse (331100201355), we get a palindrome (884202202488).

The spelling of 553102001133 in words is "five hundred fifty-three billion, one hundred two million, one thousand, one hundred thirty-three".

Divisors: 1 3 11 33 16760666701 50282000103 184367333711 553102001133