Base | Representation |
---|---|
bin | 110011100000110101… |
… | …001010101000011101 |
3 | 12021202202121111102122 |
4 | 303200311022220131 |
5 | 1401234240003432 |
6 | 41224304232325 |
7 | 3665450122625 |
oct | 634065125035 |
9 | 167682544378 |
10 | 55311641117 |
11 | 21503a856a7 |
12 | a87790b6a5 |
13 | 52a6343c35 |
14 | 2969d55885 |
15 | 168ad59612 |
hex | ce0d4aa1d |
55311641117 has 2 divisors, whose sum is σ = 55311641118. Its totient is φ = 55311641116.
The previous prime is 55311641093. The next prime is 55311641123. The reversal of 55311641117 is 71114611355.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54708742201 + 602898916 = 233899^2 + 24554^2 .
It is a cyclic number.
It is not a de Polignac number, because 55311641117 - 26 = 55311641053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55311641617) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27655820558 + 27655820559.
It is an arithmetic number, because the mean of its divisors is an integer number (27655820559).
Almost surely, 255311641117 is an apocalyptic number.
It is an amenable number.
55311641117 is a deficient number, since it is larger than the sum of its proper divisors (1).
55311641117 is an equidigital number, since it uses as much as digits as its factorization.
55311641117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12600, while the sum is 35.
The spelling of 55311641117 in words is "fifty-five billion, three hundred eleven million, six hundred forty-one thousand, one hundred seventeen".
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