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5531205165613 = 54766310099651
BaseRepresentation
bin101000001111101010110…
…0001001110001000101101
3201120210000012100111110021
41100133111201032020231
51211110402010244423
615433000042442141
71110421264111651
oct120372541161055
921523005314407
105531205165613
111842853132826
12753b99503351
1331178a18987a
141519d70caa61
1598d2cb8995d
hex507d584e22d

5531205165613 has 4 divisors (see below), whose sum is σ = 5531215812928. Its totient is φ = 5531194518300.

The previous prime is 5531205165589. The next prime is 5531205165617. The reversal of 5531205165613 is 3165615021355.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5531205165613 - 25 = 5531205165581 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5531205165613.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5531205165617) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4502163 + ... + 5597488.

It is an arithmetic number, because the mean of its divisors is an integer number (1382803953232).

Almost surely, 25531205165613 is an apocalyptic number.

It is an amenable number.

5531205165613 is a deficient number, since it is larger than the sum of its proper divisors (10647315).

5531205165613 is a wasteful number, since it uses less digits than its factorization.

5531205165613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10647314.

The product of its (nonzero) digits is 405000, while the sum is 43.

The spelling of 5531205165613 in words is "five trillion, five hundred thirty-one billion, two hundred five million, one hundred sixty-five thousand, six hundred thirteen".

Divisors: 1 547663 10099651 5531205165613