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55312211113 = 431286330491
BaseRepresentation
bin110011100000110111…
…010101110010101001
312021202210200110022121
4303200313111302221
51401234411223423
641224324351241
73665455015465
oct634067256251
9167683613277
1055312211113
1121504334975
12a877b45521
1352a64b3503
14296a0634a5
15168ae1d45d
hexce0dd5ca9

55312211113 has 4 divisors (see below), whose sum is σ = 56598541648. Its totient is φ = 54025880580.

The previous prime is 55312211081. The next prime is 55312211131. The reversal of 55312211113 is 31111221355.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31111221355 = 56222244271.

It is a cyclic number.

It is not a de Polignac number, because 55312211113 - 25 = 55312211081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55312211153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 643165203 + ... + 643165288.

It is an arithmetic number, because the mean of its divisors is an integer number (14149635412).

Almost surely, 255312211113 is an apocalyptic number.

It is an amenable number.

55312211113 is a deficient number, since it is larger than the sum of its proper divisors (1286330535).

55312211113 is a wasteful number, since it uses less digits than its factorization.

55312211113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1286330534.

The product of its digits is 900, while the sum is 25.

Adding to 55312211113 its reverse (31111221355), we get a palindrome (86423432468).

The spelling of 55312211113 in words is "fifty-five billion, three hundred twelve million, two hundred eleven thousand, one hundred thirteen".

Divisors: 1 43 1286330491 55312211113