55313021411335 has 4 divisors (see below), whose sum is σ = 66375625693608. Its totient is φ = 44250417129064.

The previous prime is 55313021411299. The next prime is 55313021411363. The reversal of 55313021411335 is 53311412031355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55313021411335 - 2¹⁵ = 55313021378567 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55313021411294 and 55313021411303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5531302141129 + ... + 5531302141138.

It is an arithmetic number, because the mean of its divisors is an integer number (16593906423402).

Almost surely, 2^{55313021411335} is an apocalyptic number.

55313021411335 is a deficient number, since it is larger than the sum of its proper divisors (11062604282273).

55313021411335 is a wasteful number, since it uses less digits than its factorization.

55313021411335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11062604282272.

The product of its (nonzero) digits is 81000, while the sum is 37.

The spelling of 55313021411335 in words is "fifty-five trillion, three hundred thirteen billion, twenty-one million, four hundred eleven thousand, three hundred thirty-five".