Base | Representation |
---|---|
bin | 111110111000100101010111… |
… | …0011110100100010100111011 |
3 | 2200112111011001022020110221020 |
4 | 1331301022232132210110323 |
5 | 1040000024112332300410 |
6 | 5240230304235313523 |
7 | 224336440446215034 |
oct | 17561125636442473 |
9 | 2615434038213836 |
10 | 553134585431355 |
11 | 150278073318154 |
12 | 520552315ab8a3 |
13 | 1a9844a17a7475 |
14 | 9a83bdd00da8b |
15 | 43e347747ba70 |
hex | 1f712ae7a453b |
553134585431355 has 16 divisors (see below), whose sum is σ = 898224520821504. Its totient is φ = 290602050852960.
The previous prime is 553134585431347. The next prime is 553134585431371.
553134585431355 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 553134585431355 - 23 = 553134585431347 is a prime.
It is a super-2 number, since 2×5531345854313552 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 275191335031 + ... + 275191337040.
It is an arithmetic number, because the mean of its divisors is an integer number (56139032551344).
Almost surely, 2553134585431355 is an apocalyptic number.
553134585431355 is a deficient number, since it is larger than the sum of its proper divisors (345089935390149).
553134585431355 is a wasteful number, since it uses less digits than its factorization.
553134585431355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550382672146.
The product of its digits is 162000000, while the sum is 60.
Adding to 553134585431355 its product of digits (162000000), we get a palindrome (553134747431355).
The spelling of 553134585431355 in words is "five hundred fifty-three trillion, one hundred thirty-four billion, five hundred eighty-five million, four hundred thirty-one thousand, three hundred fifty-five".
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