Base | Representation |
---|---|
bin | 101000001111101111001… |
… | …1001000010100100010111 |
3 | 201120210101120102212211102 |
4 | 1100133132121002210113 |
5 | 1211111203112003043 |
6 | 15433022521100315 |
7 | 1110425052243113 |
oct | 120373631024427 |
9 | 21523346385742 |
10 | 5531354016023 |
11 | 184291a15a2a0 |
12 | 75401b32769b |
13 | 3117b1c75434 |
14 | 151a0cb96743 |
15 | 98d3ac8d6b8 |
hex | 507de642917 |
5531354016023 has 4 divisors (see below), whose sum is σ = 6034204381128. Its totient is φ = 5028503650920.
The previous prime is 5531354015983. The next prime is 5531354016113. The reversal of 5531354016023 is 3206104531355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5531354016023 - 28 = 5531354015767 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5531354016623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251425182536 + ... + 251425182557.
It is an arithmetic number, because the mean of its divisors is an integer number (1508551095282).
Almost surely, 25531354016023 is an apocalyptic number.
5531354016023 is a deficient number, since it is larger than the sum of its proper divisors (502850365105).
5531354016023 is a wasteful number, since it uses less digits than its factorization.
5531354016023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 502850365104.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 5531354016023 its reverse (3206104531355), we get a palindrome (8737458547378).
The spelling of 5531354016023 in words is "five trillion, five hundred thirty-one billion, three hundred fifty-four million, sixteen thousand, twenty-three".
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