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55315764172517 is a prime number
BaseRepresentation
bin11001001001111001101000…
…11110010101011011100101
321020212010122201021100121112
430210330310132111123211
524222243141112010032
6313351413343554405
714436301126362362
oct1444746436253345
9236763581240545
1055315764172517
1116697313883aa2
1262546955bba05
1324b333c57c474
14d934239d7469
1565dd539a11b2
hex324f347956e5

55315764172517 has 2 divisors, whose sum is σ = 55315764172518. Its totient is φ = 55315764172516.

The previous prime is 55315764172511. The next prime is 55315764172519. The reversal of 55315764172517 is 71527146751355.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52445318383396 + 2870445789121 = 7241914^2 + 1694239^2 .

It is a cyclic number.

It is not a de Polignac number, because 55315764172517 - 28 = 55315764172261 is a prime.

Together with 55315764172519, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55315764172511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27657882086258 + 27657882086259.

It is an arithmetic number, because the mean of its divisors is an integer number (27657882086259).

Almost surely, 255315764172517 is an apocalyptic number.

It is an amenable number.

55315764172517 is a deficient number, since it is larger than the sum of its proper divisors (1).

55315764172517 is an equidigital number, since it uses as much as digits as its factorization.

55315764172517 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30870000, while the sum is 59.

The spelling of 55315764172517 in words is "fifty-five trillion, three hundred fifteen billion, seven hundred sixty-four million, one hundred seventy-two thousand, five hundred seventeen".