Base | Representation |
---|---|
bin | 110011100001101000… |
… | …001000011010110101 |
3 | 12021210200202021021211 |
4 | 303201220020122311 |
5 | 1401301200021042 |
6 | 41225502441421 |
7 | 3666001516111 |
oct | 634150103265 |
9 | 167720667254 |
10 | 55325001397 |
11 | 21510580456 |
12 | a880293271 |
13 | 52a9041123 |
14 | 296ba32741 |
15 | 168c0e8017 |
hex | ce1a086b5 |
55325001397 has 2 divisors, whose sum is σ = 55325001398. Its totient is φ = 55325001396.
The previous prime is 55325001317. The next prime is 55325001437. The reversal of 55325001397 is 79310052355.
It is an a-pointer prime, because the next prime (55325001437) can be obtained adding 55325001397 to its sum of digits (40).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55075171761 + 249829636 = 234681^2 + 15806^2 .
It is a cyclic number.
It is not a de Polignac number, because 55325001397 - 223 = 55316612789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55325001307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27662500698 + 27662500699.
It is an arithmetic number, because the mean of its divisors is an integer number (27662500699).
Almost surely, 255325001397 is an apocalyptic number.
It is an amenable number.
55325001397 is a deficient number, since it is larger than the sum of its proper divisors (1).
55325001397 is an equidigital number, since it uses as much as digits as its factorization.
55325001397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141750, while the sum is 40.
The spelling of 55325001397 in words is "fifty-five billion, three hundred twenty-five million, one thousand, three hundred ninety-seven".
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