Base | Representation |
---|---|
bin | 110011100001111101… |
… | …001100110100010111 |
3 | 12021211002010212110221 |
4 | 303201331030310113 |
5 | 1401304103240224 |
6 | 41230221055211 |
7 | 3666066461221 |
oct | 634175146427 |
9 | 167732125427 |
10 | 55330524439 |
11 | 21513702a53 |
12 | a8820b7507 |
13 | 52aa225cb8 |
14 | 296c66d411 |
15 | 168c8396e4 |
hex | ce1f4cd17 |
55330524439 has 2 divisors, whose sum is σ = 55330524440. Its totient is φ = 55330524438.
The previous prime is 55330524413. The next prime is 55330524443. The reversal of 55330524439 is 93442503355.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55330524439 is a prime.
It is a super-2 number, since 2×553305244392 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55330524395 and 55330524404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55330524409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27665262219 + 27665262220.
It is an arithmetic number, because the mean of its divisors is an integer number (27665262220).
Almost surely, 255330524439 is an apocalyptic number.
55330524439 is a deficient number, since it is larger than the sum of its proper divisors (1).
55330524439 is an equidigital number, since it uses as much as digits as its factorization.
55330524439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 43.
The spelling of 55330524439 in words is "fifty-five billion, three hundred thirty million, five hundred twenty-four thousand, four hundred thirty-nine".
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