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55341024511 = 173255354383
BaseRepresentation
bin110011100010100101…
…010000010011111111
312021211210220022212111
4303202211100103333
51401314300241021
641231234114451
73666254642533
oct634245202377
9167753808774
1055341024511
11215196248a3
12a88571ba27
1352ac461366
14296dc03bc3
15168d7108e1
hexce29504ff

55341024511 has 4 divisors (see below), whose sum is σ = 58596378912. Its totient is φ = 52085670112.

The previous prime is 55341024499. The next prime is 55341024521. The reversal of 55341024511 is 11542014355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55341024511 - 27 = 55341024383 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55341024521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1627677175 + ... + 1627677208.

It is an arithmetic number, because the mean of its divisors is an integer number (14649094728).

Almost surely, 255341024511 is an apocalyptic number.

55341024511 is a deficient number, since it is larger than the sum of its proper divisors (3255354401).

55341024511 is a wasteful number, since it uses less digits than its factorization.

55341024511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3255354400.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 55341024511 its reverse (11542014355), we get a palindrome (66883038866).

The spelling of 55341024511 in words is "fifty-five billion, three hundred forty-one million, twenty-four thousand, five hundred eleven".

Divisors: 1 17 3255354383 55341024511