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55341188176247 is a prime number
BaseRepresentation
bin11001001010101000111111…
…10111001101100101110111
321020221120021120000120012022
430211110133313031211313
524223202223133114442
6313411220232343355
714441161143011261
oct1445243767154567
9236846246016168
1055341188176247
11166a707aa90326
1262595abb44b5b
1324b58618acb5c
14d947563d2b31
1565e8409c93d2
hex32551fdcd977

55341188176247 has 2 divisors, whose sum is σ = 55341188176248. Its totient is φ = 55341188176246.

The previous prime is 55341188176193. The next prime is 55341188176249. The reversal of 55341188176247 is 74267188114355.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55341188176247 - 244 = 37749002131831 is a prime.

Together with 55341188176249, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 55341188176247.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55341188176249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27670594088123 + 27670594088124.

It is an arithmetic number, because the mean of its divisors is an integer number (27670594088124).

Almost surely, 255341188176247 is an apocalyptic number.

55341188176247 is a deficient number, since it is larger than the sum of its proper divisors (1).

55341188176247 is an equidigital number, since it uses as much as digits as its factorization.

55341188176247 is an evil number, because the sum of its binary digits is even.

The product of its digits is 45158400, while the sum is 62.

The spelling of 55341188176247 in words is "fifty-five trillion, three hundred forty-one billion, one hundred eighty-eight million, one hundred seventy-six thousand, two hundred forty-seven".