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55365120000 = 212355489
BaseRepresentation
bin110011100100000001…
…001011000000000000
312021220111020111200000
4303210001023000000
51401341432320000
641233454400000
73666666520011
oct634401130000
9167814214600
1055365120000
1121531192123
12a891800000
1352b4449948
1429730b7008
1516908c0000
hexce404b000

55365120000 has 780 divisors, whose sum is σ = 209571321960. Its totient is φ = 14598144000.

The previous prime is 55365119987. The next prime is 55365120043. The reversal of 55365120000 is 2156355.

55365120000 is a `hidden beast` number, since 5 + 5 + 3 + 651 + 2 + 0 + 0 + 0 + 0 = 666.

It is a super-3 number, since 3×553651200003 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a hoax number, since the sum of its digits (27) coincides with the sum of the digits of its distinct prime factors.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 622079956 + ... + 622080044.

It is an arithmetic number, because the mean of its divisors is an integer number (268681182).

Almost surely, 255365120000 is an apocalyptic number.

55365120000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 55365120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (104785660980).

55365120000 is an abundant number, since it is smaller than the sum of its proper divisors (154206201960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

55365120000 is an frugal number, since it uses more digits than its factorization.

55365120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148 (or 99 counting only the distinct ones).

The product of its (nonzero) digits is 4500, while the sum is 27.

Adding to 55365120000 its reverse (2156355), we get a palindrome (55367276355).

The spelling of 55365120000 in words is "fifty-five billion, three hundred sixty-five million, one hundred twenty thousand".