Base | Representation |
---|---|
bin | 101000010011110010001… |
… | …0000010001000010101101 |
3 | 201121121211002000010220201 |
4 | 1100213210100101002231 |
5 | 1211232001313021101 |
6 | 15441021005313501 |
7 | 1111153261455454 |
oct | 120474420210255 |
9 | 21547732003821 |
10 | 5540042313901 |
11 | 1846578504067 |
12 | 755844b65891 |
13 | 312567c8b3b4 |
14 | 1521d4a2db9b |
15 | 991988e8e01 |
hex | 509e44110ad |
5540042313901 has 2 divisors, whose sum is σ = 5540042313902. Its totient is φ = 5540042313900.
The previous prime is 5540042313893. The next prime is 5540042313929. The reversal of 5540042313901 is 1093132400455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3632187988900 + 1907854325001 = 1905830^2 + 1381251^2 .
It is a cyclic number.
It is not a de Polignac number, because 5540042313901 - 23 = 5540042313893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5540042613901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2770021156950 + 2770021156951.
It is an arithmetic number, because the mean of its divisors is an integer number (2770021156951).
Almost surely, 25540042313901 is an apocalyptic number.
It is an amenable number.
5540042313901 is a deficient number, since it is larger than the sum of its proper divisors (1).
5540042313901 is an equidigital number, since it uses as much as digits as its factorization.
5540042313901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 5540042313901 in words is "five trillion, five hundred forty billion, forty-two million, three hundred thirteen thousand, nine hundred one".
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