Base | Representation |
---|---|
bin | 101000010011110010001… |
… | …0001011010010010001101 |
3 | 201121121211002120101102211 |
4 | 1100213210101122102031 |
5 | 1211232001402121101 |
6 | 15441021015550421 |
7 | 1111153264145215 |
oct | 120474421322215 |
9 | 21547732511384 |
10 | 5540042613901 |
11 | 18465786994a4 |
12 | 75584508b411 |
13 | 312568064b03 |
14 | 1521d4aab245 |
15 | 99198957c51 |
hex | 509e445a48d |
5540042613901 has 2 divisors, whose sum is σ = 5540042613902. Its totient is φ = 5540042613900.
The previous prime is 5540042613899. The next prime is 5540042613929. The reversal of 5540042613901 is 1093162400455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5480140540900 + 59902073001 = 2340970^2 + 244749^2 .
It is a cyclic number.
It is not a de Polignac number, because 5540042613901 - 21 = 5540042613899 is a prime.
Together with 5540042613899, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5540042613961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2770021306950 + 2770021306951.
It is an arithmetic number, because the mean of its divisors is an integer number (2770021306951).
Almost surely, 25540042613901 is an apocalyptic number.
It is an amenable number.
5540042613901 is a deficient number, since it is larger than the sum of its proper divisors (1).
5540042613901 is an equidigital number, since it uses as much as digits as its factorization.
5540042613901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 5540042613901 in words is "five trillion, five hundred forty billion, forty-two million, six hundred thirteen thousand, nine hundred one".
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