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5540042613901 is a prime number
BaseRepresentation
bin101000010011110010001…
…0001011010010010001101
3201121121211002120101102211
41100213210101122102031
51211232001402121101
615441021015550421
71111153264145215
oct120474421322215
921547732511384
105540042613901
1118465786994a4
1275584508b411
13312568064b03
141521d4aab245
1599198957c51
hex509e445a48d

5540042613901 has 2 divisors, whose sum is σ = 5540042613902. Its totient is φ = 5540042613900.

The previous prime is 5540042613899. The next prime is 5540042613929. The reversal of 5540042613901 is 1093162400455.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5480140540900 + 59902073001 = 2340970^2 + 244749^2 .

It is a cyclic number.

It is not a de Polignac number, because 5540042613901 - 21 = 5540042613899 is a prime.

Together with 5540042613899, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5540042613961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2770021306950 + 2770021306951.

It is an arithmetic number, because the mean of its divisors is an integer number (2770021306951).

Almost surely, 25540042613901 is an apocalyptic number.

It is an amenable number.

5540042613901 is a deficient number, since it is larger than the sum of its proper divisors (1).

5540042613901 is an equidigital number, since it uses as much as digits as its factorization.

5540042613901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 5540042613901 in words is "five trillion, five hundred forty billion, forty-two million, six hundred thirteen thousand, nine hundred one".