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554078795293 is a prime number
BaseRepresentation
bin10000001000000011010…
…10110111011000011101
31221222011201000011010201
420010001222313120131
533034223132422133
61102312411303501
755013406023512
oct10040152673035
91858151004121
10554078795293
111a3a90042851
128b473a4ab91
1340331c3a12a
141cb63539309
15e62d614d7d
hex8101ab761d

554078795293 has 2 divisors, whose sum is σ = 554078795294. Its totient is φ = 554078795292.

The previous prime is 554078795243. The next prime is 554078795311. The reversal of 554078795293 is 392597870455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 528793661124 + 25285134169 = 727182^2 + 159013^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-554078795293 is a prime.

It is a super-2 number, since 2×5540787952932 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (554078795233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277039397646 + 277039397647.

It is an arithmetic number, because the mean of its divisors is an integer number (277039397647).

Almost surely, 2554078795293 is an apocalyptic number.

It is an amenable number.

554078795293 is a deficient number, since it is larger than the sum of its proper divisors (1).

554078795293 is an equidigital number, since it uses as much as digits as its factorization.

554078795293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 95256000, while the sum is 64.

The spelling of 554078795293 in words is "five hundred fifty-four billion, seventy-eight million, seven hundred ninety-five thousand, two hundred ninety-three".