Base | Representation |
---|---|
bin | 110011100111111101… |
… | …010000010011111101 |
3 | 12022002002120211012011 |
4 | 303213331100103331 |
5 | 1402010341431140 |
6 | 41244215011221 |
7 | 4001431305022 |
oct | 634775202375 |
9 | 168062524164 |
10 | 55431202045 |
11 | 2156551758a |
12 | a8ab969b11 |
13 | 52c504604b |
14 | 297bb99549 |
15 | 16965c4cea |
hex | ce7f504fd |
55431202045 has 4 divisors (see below), whose sum is σ = 66517442460. Its totient is φ = 44344961632.
The previous prime is 55431202039. The next prime is 55431202063. The reversal of 55431202045 is 54020213455.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 36705195396 + 18726006649 = 191586^2 + 136843^2 .
It is a cyclic number.
It is not a de Polignac number, because 55431202045 - 233 = 46841267453 is a prime.
It is a super-2 number, since 2×554312020452 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55431201998 and 55431202016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5543120200 + ... + 5543120209.
It is an arithmetic number, because the mean of its divisors is an integer number (16629360615).
Almost surely, 255431202045 is an apocalyptic number.
It is an amenable number.
55431202045 is a deficient number, since it is larger than the sum of its proper divisors (11086240415).
55431202045 is a wasteful number, since it uses less digits than its factorization.
55431202045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11086240414.
The product of its (nonzero) digits is 24000, while the sum is 31.
The spelling of 55431202045 in words is "fifty-five billion, four hundred thirty-one million, two hundred two thousand, forty-five".
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