Base | Representation |
---|---|
bin | 110011101000001010… |
… | …101011001110111111 |
3 | 12022002100012120011212 |
4 | 303220022223032333 |
5 | 1402012242021231 |
6 | 41244422235035 |
7 | 4001503230014 |
oct | 635012531677 |
9 | 168070176155 |
10 | 55434720191 |
11 | 215674aa844 |
12 | a8b0b85a7b |
13 | 52c59a84a6 |
14 | 297c43370b |
15 | 1696a6c42b |
hex | ce82ab3bf |
55434720191 has 4 divisors (see below), whose sum is σ = 55448268072. Its totient is φ = 55421172312.
The previous prime is 55434720163. The next prime is 55434720199. The reversal of 55434720191 is 19102743455.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 19102743455 = 5 ⋅3820548691.
It is a cyclic number.
It is not a de Polignac number, because 55434720191 - 26 = 55434720127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55434720199) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6767801 + ... + 6775986.
It is an arithmetic number, because the mean of its divisors is an integer number (13862067018).
Almost surely, 255434720191 is an apocalyptic number.
55434720191 is a deficient number, since it is larger than the sum of its proper divisors (13547881).
55434720191 is a wasteful number, since it uses less digits than its factorization.
55434720191 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13547880.
The product of its (nonzero) digits is 151200, while the sum is 41.
The spelling of 55434720191 in words is "fifty-five billion, four hundred thirty-four million, seven hundred twenty thousand, one hundred ninety-one".
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