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554400131 is a prime number
BaseRepresentation
bin100001000010110…
…111100110000011
31102122012110000012
4201002313212003
52113411301011
6131002415135
716511215625
oct4102674603
91378173005
10554400131
11264a4302a
121358014ab
138ab2121c
14538b6c15
1533a11a8b
hex210b7983

554400131 has 2 divisors, whose sum is σ = 554400132. Its totient is φ = 554400130.

The previous prime is 554400101. The next prime is 554400137. The reversal of 554400131 is 131004455.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 554400131 - 222 = 550205827 is a prime.

It is a super-2 number, since 2×5544001312 = 614719010505634322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 554400097 and 554400106.

It is not a weakly prime, because it can be changed into another prime (554400137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277200065 + 277200066.

It is an arithmetic number, because the mean of its divisors is an integer number (277200066).

Almost surely, 2554400131 is an apocalyptic number.

554400131 is a deficient number, since it is larger than the sum of its proper divisors (1).

554400131 is an equidigital number, since it uses as much as digits as its factorization.

554400131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 554400131 is about 23545.7030262424. The cubic root of 554400131 is about 821.5003914995.

Adding to 554400131 its reverse (131004455), we get a palindrome (685404586).

The spelling of 554400131 in words is "five hundred fifty-four million, four hundred thousand, one hundred thirty-one".