Base | Representation |
---|---|
bin | 11001001101111101001101… |
… | …10010100001110101111111 |
3 | 21021100110100201202211011121 |
4 | 30212332212302201311333 |
5 | 24232034041440203320 |
6 | 313535421512531411 |
7 | 14452333411144306 |
oct | 1446764662416577 |
9 | 237313321684147 |
10 | 55455121022335 |
11 | 16740426117961 |
12 | 62776a79b0b67 |
13 | 24c351ab18208 |
14 | d9a083a4943d |
15 | 6627acece8aa |
hex | 326fa6ca1d7f |
55455121022335 has 8 divisors (see below), whose sum is σ = 66781290618000. Its totient is φ = 44207333223744.
The previous prime is 55455121022311. The next prime is 55455121022341. The reversal of 55455121022335 is 53322012155455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55455121022335 - 27 = 55455121022207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55455121022291 and 55455121022300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19595447710 + ... + 19595450539.
It is an arithmetic number, because the mean of its divisors is an integer number (8347661327250).
Almost surely, 255455121022335 is an apocalyptic number.
55455121022335 is a deficient number, since it is larger than the sum of its proper divisors (11326169595665).
55455121022335 is a wasteful number, since it uses less digits than its factorization.
55455121022335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39190898537.
The product of its (nonzero) digits is 900000, while the sum is 43.
The spelling of 55455121022335 in words is "fifty-five trillion, four hundred fifty-five billion, one hundred twenty-one million, twenty-two thousand, three hundred thirty-five".
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