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55534052545 = 511106810509
BaseRepresentation
bin110011101110000101…
…100110010011000001
312022100021010011112221
4303232011212103001
51402213204140140
641302331251041
74004120441506
oct635605462301
9168307104487
1055534052545
11216085856a4
12a91a2a9a81
13531044712a
14298b6cd4ad
1516a063e14a
hexcee1664c1

55534052545 has 4 divisors (see below), whose sum is σ = 66640863060. Its totient is φ = 44427242032.

The previous prime is 55534052537. The next prime is 55534052551. The reversal of 55534052545 is 54525043555.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54525043555 = 510905008711.

It can be written as a sum of positive squares in 2 ways, for example, as 19658283264 + 35875769281 = 140208^2 + 189409^2 .

It is a cyclic number.

It is not a de Polignac number, because 55534052545 - 23 = 55534052537 is a prime.

It is a super-3 number, since 3×555340525453 (a number of 33 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5553405250 + ... + 5553405259.

It is an arithmetic number, because the mean of its divisors is an integer number (16660215765).

Almost surely, 255534052545 is an apocalyptic number.

It is an amenable number.

55534052545 is a deficient number, since it is larger than the sum of its proper divisors (11106810515).

55534052545 is a wasteful number, since it uses less digits than its factorization.

55534052545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11106810514.

The product of its (nonzero) digits is 1500000, while the sum is 43.

The spelling of 55534052545 in words is "fifty-five billion, five hundred thirty-four million, fifty-two thousand, five hundred forty-five".

Divisors: 1 5 11106810509 55534052545