Base | Representation |
---|---|
bin | 101000011010110100000… |
… | …1010001011101011000001 |
3 | 201200001210021100220112011 |
4 | 1100311220022023223001 |
5 | 1212003411343312231 |
6 | 15451555101532521 |
7 | 1112226360501340 |
oct | 120655012135301 |
9 | 21601707326464 |
10 | 5555140213441 |
11 | 1851a15912495 |
12 | 758759274141 |
13 | 313b02b93b70 |
14 | 152c27c59b57 |
15 | 9977e0ea9b1 |
hex | 50d6828bac1 |
5555140213441 has 64 divisors (see below), whose sum is σ = 7220557209600. Its totient is φ = 4153461751296.
The previous prime is 5555140213417. The next prime is 5555140213531. The reversal of 5555140213441 is 1443120415555.
It is not a de Polignac number, because 5555140213441 - 217 = 5555140082369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5555140213394 and 5555140213403.
It is not an unprimeable number, because it can be changed into a prime (5555140213241) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 234510900 + ... + 234534586.
It is an arithmetic number, because the mean of its divisors is an integer number (112821206400).
Almost surely, 25555140213441 is an apocalyptic number.
It is an amenable number.
5555140213441 is a deficient number, since it is larger than the sum of its proper divisors (1665416996159).
5555140213441 is a wasteful number, since it uses less digits than its factorization.
5555140213441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25078.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 5555140213441 its reverse (1443120415555), we get a palindrome (6998260628996).
The spelling of 5555140213441 in words is "five trillion, five hundred fifty-five billion, one hundred forty million, two hundred thirteen thousand, four hundred forty-one".
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