Base | Representation |
---|---|
bin | 11001010000110111010110… |
… | …00001010100111010110111 |
3 | 21021201000021221202212011111 |
4 | 30220123223001110322313 |
5 | 24240203220300000210 |
6 | 314053345421415451 |
7 | 14462501633350624 |
oct | 1450335301247267 |
9 | 237630257685144 |
10 | 55555050000055 |
11 | 16779845453961 |
12 | 6292b35a0a587 |
13 | 24cca849bba28 |
14 | da0c4349d34b |
15 | 6651aad8a88a |
hex | 3286eb054eb7 |
55555050000055 has 4 divisors (see below), whose sum is σ = 66666060000072. Its totient is φ = 44444040000040.
The previous prime is 55555050000001. The next prime is 55555050000083. The reversal of 55555050000055 is 55000005055555.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 55555050000055 - 213 = 55555049991863 is a prime.
It is a super-2 number, since 2×555550500000552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55555049999972 and 55555050000017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5555505000001 + ... + 5555505000010.
It is an arithmetic number, because the mean of its divisors is an integer number (16666515000018).
Almost surely, 255555050000055 is an apocalyptic number.
55555050000055 is a deficient number, since it is larger than the sum of its proper divisors (11111010000017).
55555050000055 is a wasteful number, since it uses less digits than its factorization.
55555050000055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11111010000016.
The product of its (nonzero) digits is 390625, while the sum is 40.
The spelling of 55555050000055 in words is "fifty-five trillion, five hundred fifty-five billion, fifty million, fifty-five", and thus it is an aban number.
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