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55611331 is a prime number
BaseRepresentation
bin1101010000100…
…0111111000011
310212122100101221
43110020333003
5103214030311
65303535511
71243455106
oct324107703
9125570357
1055611331
1129433686
121675a597
13b6a1519
14755873d
154d37671
hex3508fc3

55611331 has 2 divisors, whose sum is σ = 55611332. Its totient is φ = 55611330.

The previous prime is 55611329. The next prime is 55611343. The reversal of 55611331 is 13311655.

55611331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55611331 - 21 = 55611329 is a prime.

It is a super-2 number, since 2×556113312 = 6185240271183122, which contains 22 as substring.

Together with 55611329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 55611296 and 55611305.

It is not a weakly prime, because it can be changed into another prime (55641331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27805665 + 27805666.

It is an arithmetic number, because the mean of its divisors is an integer number (27805666).

Almost surely, 255611331 is an apocalyptic number.

55611331 is a deficient number, since it is larger than the sum of its proper divisors (1).

55611331 is an equidigital number, since it uses as much as digits as its factorization.

55611331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1350, while the sum is 25.

The square root of 55611331 is about 7457.3005169431. The cubic root of 55611331 is about 381.6990653664.

Adding to 55611331 its reverse (13311655), we get a palindrome (68922986).

It can be divided in two parts, 556 and 11331, that multiplied together give a palindrome (6300036).

The spelling of 55611331 in words is "fifty-five million, six hundred eleven thousand, three hundred thirty-one".