Base | Representation |
---|---|
bin | 11001010011011011110010… |
… | …00111100001011001111111 |
3 | 21022000110011120102221001211 |
4 | 30221231321013201121333 |
5 | 24243130021313202110 |
6 | 314202105555545251 |
7 | 14502045446332033 |
oct | 1451557107413177 |
9 | 238013146387054 |
10 | 55643333334655 |
11 | 16803229059910 |
12 | 62a80738bb227 |
13 | 25081b3c7b061 |
14 | da521a3b81c3 |
15 | 66762667098a |
hex | 329b791e167f |
55643333334655 has 16 divisors (see below), whose sum is σ = 72849029299200. Its totient is φ = 40464074633760.
The previous prime is 55643333334553. The next prime is 55643333334661.
55643333334655 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55643333334655 - 217 = 55643333203583 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55643333334655.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46961475 + ... + 48131764.
It is an arithmetic number, because the mean of its divisors is an integer number (4553064331200).
Almost surely, 255643333334655 is an apocalyptic number.
55643333334655 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55643333334655 is a deficient number, since it is larger than the sum of its proper divisors (17205695964545).
55643333334655 is a wasteful number, since it uses less digits than its factorization.
55643333334655 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95103894.
The product of its digits is 262440000, while the sum is 58.
It can be divided in two parts, 5564333 and 3334655, that added together give a palindrome (8898988).
The spelling of 55643333334655 in words is "fifty-five trillion, six hundred forty-three billion, three hundred thirty-three million, three hundred thirty-four thousand, six hundred fifty-five".
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