Base | Representation |
---|---|
bin | 110011110110000001… |
… | …001011000011100011 |
3 | 12022200112111012020002 |
4 | 303312001023003203 |
5 | 1403001240010430 |
6 | 41323443210215 |
7 | 4010324425451 |
oct | 636601130343 |
9 | 168615435202 |
10 | 55667110115 |
11 | 216766a5831 |
12 | a95697696b |
13 | 5331b93516 |
14 | 29a12479d1 |
15 | 16ac173845 |
hex | cf604b0e3 |
55667110115 has 4 divisors (see below), whose sum is σ = 66800532144. Its totient is φ = 44533688088.
The previous prime is 55667110073. The next prime is 55667110117. The reversal of 55667110115 is 51101176655.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51101176655 = 5 ⋅10220235331.
It is a cyclic number.
It is not a de Polignac number, because 55667110115 - 222 = 55662915811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55667110117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5566711007 + ... + 5566711016.
It is an arithmetic number, because the mean of its divisors is an integer number (16700133036).
Almost surely, 255667110115 is an apocalyptic number.
55667110115 is a deficient number, since it is larger than the sum of its proper divisors (11133422029).
55667110115 is a wasteful number, since it uses less digits than its factorization.
55667110115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11133422028.
The product of its (nonzero) digits is 31500, while the sum is 38.
The spelling of 55667110115 in words is "fifty-five billion, six hundred sixty-seven million, one hundred ten thousand, one hundred fifteen".
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