55705047544471 has 4 divisors (see below), whose sum is σ = 59990051201752. Its totient is φ = 51420043887192.

The previous prime is 55705047544451. The next prime is 55705047544501. The reversal of 55705047544471 is 17444574050755.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55705047544471 - 2⁵ = 55705047544439 is a prime.

It is a super-3 number, since 3×55705047544471³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55705047544411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2142501828621 + ... + 2142501828646.

It is an arithmetic number, because the mean of its divisors is an integer number (14997512800438).

Almost surely, 2^{55705047544471} is an apocalyptic number.

55705047544471 is a deficient number, since it is larger than the sum of its proper divisors (4285003657281).

55705047544471 is a wasteful number, since it uses less digits than its factorization.

55705047544471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4285003657280.

The product of its (nonzero) digits is 54880000, while the sum is 58.

The spelling of 55705047544471 in words is "fifty-five trillion, seven hundred five billion, forty-seven million, five hundred forty-four thousand, four hundred seventy-one".